For copper-silver systems, converting ionization cell current to ppm?

For copper-silver ionization systems, what are the calculations to convert ionization cell current (assume 100mA) to ppm for a given water flow rate please? Assume pH of 7 and potable water.

The generating capacity is flow dependent. At 6 gallons per minute, the system will generate 0.5ppm (mg/L) per amp. If using 70:30 electrodes: 7 amps at 6 gpm = 3.5 ppm copper or 0.5 ppm per amp. At 100mA output and a 6 gpm flow rate. 0.05 ppm of copper would be generated.